Question

a bag contains 7 green balls , 3 blue balls and 5 black balls .one ball drawn at randomly from the bag .what is the probability that the ball drawn is (1) green ball (2) not green ball ​

Answer 1

Answer:

1- probability of getting green ball

P(A)=n(A)/n(s)

p(A)=7/15

2-probability of not getting a green ball

P(B)=n(B)/n(s)

=8/15

Step-by-step explanation:

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