A bag contains 7 green balls and 3 yellow balls. Sani takes three balls out of the bag, without replacement.
i) Find the probability that all three balls he chooses are yellow
ii) Find the probability that atleast one of the three balls he chooses is green.
Answers
Answered by
2
Answer:
i) 3/10
ii) 7/10
Answered by
2
Answer:
i) 1/120
As this is without replacement so you will not keep the ball back.
3/10*2/9*1/9
=1/120
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