Question

a bag contains 7 red 5 Blue Balls A ball is taken random from the bag its colour is noted and not replace into the bag now second ball its colour is noted find the probability that is one is red and other is blue ​

Answer 1

35/66 is the probability that one is red and other is blue ​ if Ball not replaced and 35/72 if ball replaced

Step-by-step explanation:

Red Balls = 7

Blue Balls  = 5

if ball not replaced

Two possibilities

1st Red  , 2nd blue  of   1st Blue 2nd Red

= (7/12)(5/11)  + (5/12)(7/11)

= 35/132 + 35/132

= 2 * 35/132

= 35/66

another way

⁷C₁*⁵C₁/¹²C₂

= (7 * 5) /( 12 * 11 /2)

= 35/66

if Ball is replaced

(7/12)(5/12)  + (5/12)(7/12)

= 70/144

= 35/72

Learn more:

An urn contains 6 red balls and 3 blue balls. One ball is selected at ...

https://brainly.in/question/15063077

Two balls are drawn from an urn containing 5 green, 3 blue, 7 yellow ...

https://brainly.in/question/7795905

2)An urn contains 6 red balls and 3 blue balls. One ball is selected at

https://brainly.in/question/14984484