a bag contains 7 red balls and 3 Green balls A ball is drawn at random from the bag what is the probability what is the probability that the ball is first red second green
Answers
Answered by
4
Answer:
p(red) = 7/10
p(green) = 3/10
Answered by
2
Given:
Total number of red balls = 7
Total number of green balls = 3
To find:
A ball is drawn from the bag then what will be the probability that the first ball is red and second is green.
Solution:
It is given that the balls are drawn through replacement.
Hence of probability of drawing a red ball will be 7/10.
And the probability of drawing a green ball will be 3/10.
Total probability will be 7/10 × 3/10 = 21/100 = 0.21.
Thus the required probability is 0.21.
Similar questions