Math, asked by hemjith2006, 8 days ago

A bag contains 7 red balls and 5 white balls. Determine the number of ways in which 3 red balls and 2 white balls can be selected.​

Answers

Answered by viditu356
9

Answer:

red balls white balls

7 5

no. of ways in which red balls selected = 7C3

no. of ways in which white balls selected = 5C2

7C3 × 5C2 = 35 × 10 = 350 waystl

Answered by pulakmath007
0

SOLUTION

GIVEN

A bag contains 7 red balls and 5 white balls.

TO DETERMINE

The number of ways in which 3 red balls and 2 white balls can be selected.

EVALUATION

Total number of red balls = 7

The number of ways in which 3 red balls can be selected

 \sf{ =  {}^{7} C_3}

\displaystyle \sf{ =  \frac{7!}{3! \: 4!}  }

\displaystyle \sf{ =  \frac{7 \times 6 \times 5}{3 \times 2}  }

\displaystyle \sf{ =35}

Total number of white balls = 5

The number of ways in which 2 white balls can be selected

 \sf{ =  {}^{7} C_3}

\displaystyle \sf{ =  \frac{5!}{2! \: 3!}  }

\displaystyle \sf{ =  \frac{5 \times 4}{2}  }

\displaystyle \sf{ = 10 }

Hence the required total number of ways

= 35 × 10

= 350

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