Question

A bag contains 7 white ball 5 black balls and 4 red balls if two balls are drawn at random from the bag find the probability that one is black and the other one is red​

Answer 1

Answer:

black= 5/16      red= 4/16= 1/4

Step-by-step explanation:

Answer 2

Answer:

There are total 16 balls in the bag .

Out of these 16 balls, two balls can be drawn in 16C2    

=120 ways .

Out of 5 black balls, one black ball can be drawn in 5C1 ways .

Out of 4 red balls, one red ball can be drawn in 4C1 ways .

Therefore, one black one red balls can be drawn is 5C2 X 4C2 ways .

∴ Favourable number of ways = 5C1 X 4C1 .

Hence, required probability = 5C1 X 4C1

                                                      16C2

= 5 X 4

    20

= Required probability = 1

                                        6

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