Question

A bag contains 700 coins of denomination 1 rupee, 50 p and 25 p. The value if the respective coins is 2:3:5. Find the no. of each kind of coin. ​

Answer 1

$\large{\bf{\underline{ Required\: answer}}}$

• Number of coins of 1 rupees = 140
• Number of coins of 50 paisa = 210
• Number of coins of 25 paisa = 350

$\large{\bf{\underline{ Explanation}}}$

GivEn:

• Total number of coins = 700
• Ratio of ₹1, 50 paise and 25paisa = 2:3:5 respectively.

To finD:

• Number of each kind of coins.

Solution:

Here, we have that ratio of coins of 1 rupees, 50 paisa and 25 paisa are 2:3:5 respectively.

Hence,

Supposing that coins of 1 rupees = 2x, coins of 50 paisa = 3x and coins of 25 paisa = 5x •••[ x as constant of ratio]

Now, we can say that sum of total coins is equal to 700 or sum of 2x,3x and 5x are equal to 700. •••[as given in question]

According to the given condition :

2x + 3x + 5x = 700

⟾ 10x = 700

⟾ x = 700/10

⟾ x = 70

Hence,

Constant of ratio or value of x = 70.

Therefore, putting the value of x .

• 2x = 2×70 = 140
• 3x = 3×70 = 210
• 5x = 5×70 = 350

Hence,

Number of each coins are :-

• Number of coins of 1 rupees = 140
• Number of coins of 50 paisa = 210
• Number of coins of 25 paisa = 350

Answer 2

Step-by-step explanation:

Here, we have that ratio of values of coins of 1 rupees, 50 paisa and 25 paisa are 2:3:5 respectively.

Hence,

Supposing that

value of  1 rupees coin = 2x,

value of 50 paisa coin = 3x

value of 25 paisa coin = 5x •••[ x as constant of ratio]

now

no of coin = total value of coin/face value of coin

so, no of 1 rupee = 2x÷ 1= 2x

no of 50 paisa or 1/2 rupees = 3x÷1/2 = 6x

no of 25 paisa or 1/4 rupees = 5x ÷ 1/4 = 20x

now by the problem

2x + 6x + 20x = 700

or 28x = 700

or x= 25

therefore,

no of 1 rupee = 2x25 = 50

no of 50 paisa = 6x25 = 150

no of 25 paisa = 20x25 = 500

And hence the answer.