Question

A bag contains 8 green, 12 blue, 4 red and 6 yellow marbles. If a marble is drawn at random,
what is the probability of getting:
(a) a yellow marble
(b) a red marble
(c) a green marble
​

Answer 1

Answer:

Total no of marble = 8+12+4+6

= 30

a) Probability of getting yellow marble = No of yellow marble/ Total no of marbles

= 6/30

= 1/5

b) Probability of getting a red marble = No of red marble / Total no of marbles

= 4/30

=2/15

c) Probability of getting a green marble = No of green marble/ Total no of marbles

= 8/30

= 4/15

Hope it will help you.

Answer 2

Question:-

A bag contains 8 green, 12 blue, 4 red and 6 yellow marbles. If a marble is drawn at random,

what is the probability of getting:

(a) a yellow marble

(b) a red marble

(c) a green marble

Answer:-

Probability of an event = Number of outcomes/Total Number of outcomes.

Total number of marbles = 30

Yellow marbles = 6

Blue marbles = 12

Green marbles = 8

Red marbles = 4

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(a) Probability of getting an yellow marble

⟹ P(a yellow marble) = No.of marbles/Total number of marbles

⟹ 6/30 = 1/5

⟹ P(a yellow marble) = 1/5

(b) Probability of getting a red marble

⟹ P(a red marble) = No.of marbles/Total number of marbles

⟹ 4/30 = 2/15

⟹ P(a red marble) = 2/15

(c) Probability of getting a green marble

⟹ P(a green marble) = No.of marbles/Total number of marbles

⟹ 8/30 = 4/15

⟹ P(a green marble) = 4/15

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