A bag contains 8 red and 4 blue balls. Two balls are chosen at random from the bag. Find the probability of getting the balls of the same colour.
Answers
Answered by
3
Answer:
Total number of bassl =3+4+5=12
Favourable number of cases are total minus the balls drawn from same colour
12
C
2
−(
3
C
2
+
4
C
2
+
5
C
2
)
=66−(3+6+10)=66−19=47
Total number of cases =
12
C
2
=66
Hence the required probability
=
Totalnumberofcases
Favourablecases
=
66
47
Answered by
1
Answer:
If the balls are not replaced: 3!(8/25)*(5/24)(12/23)=24/115=0.208695…
If the balls are replaced: 3!(8/25)(5/25)*(12/25)=0.18432.
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