Question

A bag contains 8 red and 4 blue balls. Two balls are chosen at random from the bag. Find the probability of getting the balls of the same colour.​

Answer 1

Answer:

Total number of bassl =3+4+5=12

Favourable number of cases are total minus the balls drawn from same colour

12

C

2

−(

3

C

2

+

4

C

2

+

5

C

2

)

=66−(3+6+10)=66−19=47

Total number of cases =

12

C

2

=66

Hence the required probability

=

Totalnumberofcases

Favourablecases

=

66

47

Answer 2

Answer:

If the balls are not replaced: 3!(8/25)*(5/24)(12/23)=24/115=0.208695…

If the balls are replaced: 3!(8/25)(5/25)*(12/25)=0.18432.