Question

A bag contains 8 red and 4 green balls. Find the probability that two balls are red and one ball is green when three balls are drawn at random.
A) 56/99 B) 112/495 C) 78/495 D) None of these

Answer 1

Explanation:

n(S)= C4 12=495

n(E)= C28×C14=112

hence,

$answer \: is \: b$

Answer 2

Answer:

d

Step-by-step explanation:

n(s) 12c3

n(p) 8c2+4c1/12c3