A bag contains 8 red and 5 white balis. Two successive draws of 3 balis are made without replacement. The probability at the First draw will produce 3 white balls and second 3 red balls is?
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Step-by-step explanation:
A bag contain 8 red and 5 white balls
⇒P(A∩B)=P(A)P(
A
B
)
A is the event such that the first drawing will give 3 white balls.
B is the event such that the second drawing will give 3 blue balls.
⇒P(A)=
3!10!
13!
3!2!
5!
=
2!3!
5!10!
=
143
5
⇒P(
A
B
)=
3!7!
10!
3!5!
8!
=
5!10!
8!7!
=
15
7
⇒P(A∩B)=P(A)(
A
B
)=
143
5
×
15
7
=
429
7
=0.01632
Hence, the answer is
429
7
.
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