A bag contains 8 red balls and some blue balls. If one ball is drawn randomly the probability of drawing a red ball to a blue ball are in the ratio 5:2, determine the probability of drawing a blue ball from the
bag ?
Answers
Solution :-
Let us assume that, there are x blue balls in the bag .
so,
→ Total balls in bag = (8 + x) .
then,
→ Probability of drawing a red ball = 8/(8 + x)
and,
→ Probability of drawing a red ball = x/(8 + x)
A/q,
→ 8/(8 + x) / x/(8 + x) = 5/2
→ 8 / x = 5/2
→ x = (16/5) .
therefore,
→ The probability of drawing a blue ball from the bag = (16/5) / (16/5 + 8) = (16/5) / (56/5) = (16/56) = (2/7) (Ans.)
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Given : A bag contains 8 red balls and some blue balls.
If one ball is drawn randomly the probability of drawing a red ball to a blue ball are in the ratio 5:2
To Find : probability of drawing a blue ball from the bag
Solution:
probability of drawing a red ball to a blue ball are in the ratio 5:2
probability of drawing red ball = 5P
probability of drawing Blue ball =2P
Total Probability = 5P + 2P = 7P
probability of drawing a blue ball from the bag = 2P/7P = 2/7
additional info
To find number of blue balls in Bags
Let say blue balls = B
Total Balls = 8 + B
B /(8 + B) = 2/7
=> 7B = 16 + 2B
=> 5B = 16
=> B = 16/5
Balls should be in integer
looks problem with data
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