Question

A BAG CONTAINS 8 RED BALLS AND SOME GREEN BALLS. IF PROBABILITY OF TAKING OUT A RED BALL IS 1/2 OF GREEN BALL THEN GREEN BALLS IN BAG ARE​

Answer 1

no.of green balls =X

red balls =8

total balls=8+X

P(R) =1/2 P(G)

X/(8+x) =1/2 × 8/(X+8)

X = 4

hence no of green balls =4

I hope this helps you

Answer 2

Answer:

$\huge\pink{AnSwEr:}$

Let the no. of green balls be x

so,the total outcome is 8+x

P(R)= 1/2P(G)

x/(8+x)=1/2×8/(x+8)

x=4

hence,the no. of green ball is 4