Question

A bag contains 8 white balls, and 3 blue balls. another bag contains 7 white, and 4 blue balls. what is the probability of getting blue ball?

Answer 1

=1/2(3c1/11c1)+1/2(4c1/11c1)

=3/22+22

=>7/22

Answer 2

Answer:

$\frac{7}{22}$

Step-by-step explanation:

Bag 1:

White balls = 8

Blue balls = 3

Total balls = 8+3=11

Bag 2:

White balls = 7

Blue balls = 4

Total balls = 7+4=11

Total blue balls = 3+4=7

Total balls in both bags = 11+11=22

So, Probability of getting blue ball =$\frac{\text{No. of blue balls}}{\text{Total no. of balls}}$

                                                        =$\frac{7}{22}$

Hence the probability of getting blue ball is $\frac{7}{22}$