A bag contains 8 white balls and 5 blue balls. In how many ways can 5 white balls and 3 blue balls be drawn?
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Answer:
orrect option is
C
429
7
A bag contain 8 red and 5 white balls
⇒P(A∩B)=P(A)P(
A
B
)
A is the event such that the first drawing will give 3 white balls.
B is the event such that the second drawing will give 3 blue balls.
⇒P(A)=
3!10!
13!
3!2!
5!
=
2!3!
5!10!
=
143
5
⇒P(
A
B
)=
3!7!
10!
3!5!
8!
=
5!10!
8!7!
=
15
7
Step-by-step explanation:
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