Question

A bag contains 870rs in a form of rs1, 50,25paise in the ratio of 3:5:7 find the no of each type of coins?

Answer 1

Step-by-step explanation:

given

a bag contain ₹870

in the form of 1₹ 50p and 25p

the ratio of coins=3:5:7

let

number of coins be X

so,

number of ₹1 coins=3x

number of 50p coins=5x*50/100=5x/2

number of 25p coins=7x*25/100=7x/4

$now \\ sum \: of \: coins = total \: money \\ = > 3x + \frac{5x}{2} + \frac{7x}{4} = 870 \\ = > \frac{12x + 10x + 7x}{4} = 870 \\ = > \frac{29x}{4} = 870 \\ = > 29x = 870 \times 4 \\ = > x = \frac{870 \times 4}{29} \\ = > x = 120$

hence

number of ₹1coins=3*120=360

number of 50p coins=5*120=600

number of 25p coins=7*120=840

I hope you dear it will be helpful