Question

A bag contains 8black and 6green balls in how many ways a child can pick 7balls from bag so that the picked balls contain atleast 6black balls

Answer 1

at one 6 black ball and 2 green

another 7 black and 1 green
another 8 black

Answer 2

Answer:

176 ways.

Step-by-step explanation:

No. of Black balls in the bag = 8

No. of non-black balls (green) in the bag = 6

To pick random of 7 balls with atleast 6 black balls is possible in two scenarios.

6 Black balls and 1 non-Black ball can be picked in (8C6)*(6C1) = 28*6 = 168 ways.

7 Black balls can be drawn in (8C7) = 8 ways.

So, 7 balls can be picked up from the bag in (168+8) =  176 ways, such that it will contain at least 6 Black balls.