Question

A bag contains 9 white balls, 6 green balls and 7 blue balls. They are mixed thoroughly and one ball is drawn at random. Find the probability of getting a) a blue ball b) a red ball c) a white ball d) a green ball​

Answer 1

Step-by-step explanation:

A bag contains 6 red balls, 8 white balls, 5 green balls and 2 black balls. One ball is drawn at random from the bag.

Then total number of balls in bag =6+8+5+2+1=22

Total number of out come =22

(i)The event is getting a White ball=number of white ball in bag=8

Then probability=

22

8

=

11

4

(ii)The event getting the Red or black=The number of red & black ball in bag=6+8+1=9 (one ball is random)

The probability=

22

9

(iii)The event getting the Not green is total number of ball other then green ball=6+8+2+1=17

The probability=

22

17

(iv) The event getting the Neither white nor black=Total number of balls without white or black ball in bag=6+5=11

The probability=

22

11

=

2

1