A bag contains 90 identical marble stones which are numbered from 1 to 90. If one stone is drawn
at random from the bag, find the probability that it has
(i) a number divisible by 3
(ii) a number divisible by 3 and 4.
Answers
Answered by
0
Answer: (1) All the multiples of 3 will be 30 till 90
P(E) = Total number of outcomes/All possible outcomes
30/90 = 1/3 or 33.3%
(2) All multiples of 3 and 4...Some will be common
53/90
Answered by
0
Answer:
No. of possible outcomes ÷ the total no.
Divisible by3
90÷3 = 30
30÷90=1/3
Step-by-step explanation:
Similar questions