Question

a bag contains a bag contains 10 paise,25 paise and 50 paise coins. the number of 25 paise coins is three times the number of 10 paise coins if 50 paise coins are 5 more than 25 paise coins and the total value of the money in the bag is ₹120, find the number of 10 paise coins.

Answer 1

let the number of 25 paise coin = x
........................... of 50 paise coin = y
........................... of 10 paise coin = z
here the number of 25 paise coin=3z (10× 3)
here the number of 50 paise coin=x +5
then make equation:
x +y+z = 120
3z+(3z+5)+z =120
7z+5=120
7z=120-5
7z=115
z=115÷7
z=?
then you do
z ×3=25 paise coin
z×3+5=50paise coin
z=10paise coin

Answer 2

Answer: see explanation

Explanation:let the number of 25 paise coin = x

........................... of 50 paise coin = y

........................... of 10 paise coin = z

here the number of 25 paise coin=3z (10× 3)

here the number of 50 paise coin=x +5

then make equation:

x +y+z = 120

3z+(3z+5)+z =120

7z+5=120

7z=120-5

7z=115

z=115÷7

z=?

then you do

z ×3=25 paise coin

z×3+5=50paise coin

z=10paise coin