Question

A bag contains a red, a blue, a yellow and a white ball all of the same size. What is a probability that the ball drawn at random (i) is not a blue ball? (ii) is either blue or yellow?​

Answer 1

Answer:

(I) Probability = 3/4

(2) Probability= 2/4= 1/2.

Answer 2

The probability of not a blue ball is 3/4 and the probability of either blue or yellow is 1/2.

Given:

• A bag contains a red, a blue, a yellow and a white ball all of the same size.

To find:

• What is the probability that the ball drawn at random (i) is not a blue ball?
• (ii) is either blue or yellow?

Solution:

Formula to be used:

Probability an event

$P(E) = \frac{ \text{Favourable Outcome}}{ \text{Total Outcomes}}$

Step 1:

Find the probability of not a blue ball.

Total balls in bag:4

Not a Blue ball :3

Let the probability of not ab blue ball is

$\bf P(\bar B) = \frac{3}{4}$

Step 2:

Find the probability of either a blue or yellow.

Probability of choosing a blue ball

$\bf P(B) = \frac{1}{4}$

Probability of choosing a yellow ball

$\bf P(Y) = \frac{1}{4}$

Let the probability of selecting either blue or yellow is

P(BY).

$P(BY) = \frac{1}{4} + \frac{1}{4}$

$\bf P(BY) = \frac{1}{2}$

Thus,

Probability of not a blue ball is 3/4 and probability of either blue or yellow is 1/2.

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