A bag contains a red ball a blue ball and 2 white ball. If one ball is drawn at random then what is the probability that the ball is I) Red II) Blue III) White
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1
Step-by-step explanation:
Probability of selecting a bag out of three =
3
1
Probability of getting a red and white ball from bag A =
6
C
2
1
C
1
×
3
C
1
=
15
3
=
5
1
Probability of selecting a red and a white ball from bag B =
8
C
2
2
C
1
×
3
C
1
=
28
6
=
14
3
Probability of selecting a red and a white ball from bag C =
9
C
2
4
C
1
×
2
C
1
=
36
8
=
9
2
So the probability that balls are white and red =
3
1
(
5
1
+
14
3
+
9
2
)=
3
1
(
630
126+135+140
)=
1890
401
please mark my answer as brainlist
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