Question

A bag contains a red ball, a blue ball and a yellow ball, all the balls being of the same size. Kritika takes out a ball from the bag without looking into it. What is the probability that she takes out the

(i) yellow ball?

(ii) red ball?

(iii) blue ball?

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Answer 1

Answer:

GIVEN :-

• A bag contains a red ball, a blue ball and a yellow ball, all the balls being of the same size. Kritika takes out a ball from the bag without looking into it
• Kritika takes out a ball from the bag without looking into it. So, it is equally likely that she takes out any one of them from the bag.

• Let Y be the event ‘the ball taken out is yellow’, B be the event ‘the ball taken out is blue’, and R be the event ‘the ball taken out is red’.
• The number of possible outcomes = Number of balls in the bag = n(S) = 3.

TO FIND :-

What is the probability that she takes out the

(i) yellow ball?

(ii) red ball?

(iii) blue ball?

FORMULAE :-

$P(E) = \frac{Number \: of \: favourable \: outcomes}{Total \: number \: of \: outcomes}$

SOLUTION :

➡️(i) The number of outcomes favourable to the event Y = n(Y) = 1.

P(Y) = n(Y)/n(S) =1/3

➡️Similarly, (ii) P(R) = 1/3

➡️and (iii) P(B) = ⅓

Answer 2

Answer:

yellow ball : 1/3

red ball: 1/3

blue ball:1/3

Step-by-step explanation:

Probability= Favourable outcomes / total no. of outcomes