Question

A bag contains a red counter, a blue counter, and a green counter. If a counter is taken out of the bag at random:
A. What are the possible outcomes?
B. What is the probability of taking out:
a. A red counter?
b. A red or green counter?
C. A counter that is not blue?
d. A yellow counter?​

Answer 1

Step-by-step explanation:

White               6Red                9Green

Total number of balls =5+6+9

                                  =20

(i) Probability =Total casesfavourable cases

    P(Green) =209

(ii)  P(White or red) =205+6

                               =2011

(iii) P(neither green nor white) = P(Red)

                                                =206

                                                =103