A bag contains a total at 105 coins of Re. 1, 50 paise and 25 paise denominations. Find the total number of coins of Re. 1 if there are a total of 50.50 rupees in the bag and it is known that the number of 25 paise coins is 133.33% more than the number of Re. 1 coins.
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Let there are X one rupee's coin, Y 50 paise's coins and Z 25 paise's coins.
Now,
X +Y +Z = 220 ---------------- (1)
Total amount = Rs. 160
Now,
X + (Y/2) + (Z/4) = 160
4X +2Y +Z = 640 ---------------- (2)
Thrice as many 1 Re coins as 25 paise,
X = 3Z -------- (3)
On Solving equations 1, 2 and 3,
Z = 40
X = 3*40 = 120
Y = 220 - (120+40)= 60
50 paise's coins = 60.
Now,
X +Y +Z = 220 ---------------- (1)
Total amount = Rs. 160
Now,
X + (Y/2) + (Z/4) = 160
4X +2Y +Z = 640 ---------------- (2)
Thrice as many 1 Re coins as 25 paise,
X = 3Z -------- (3)
On Solving equations 1, 2 and 3,
Z = 40
X = 3*40 = 120
Y = 220 - (120+40)= 60
50 paise's coins = 60.
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