Question

A bag contains an equal number of one rupee coins, 50 paisa coins and 25 paisa coins respectively. if the total value is rs. 35/- .how many coins of each type are there

Answer 1

1 rupees + 50 paise + 25 paise = 1.75 rupees.
1.75 * x = 35
x = 35/1.75 = 20
1*20=20 rupees
50*20=1000/100= 10 rupees
25*20=500/100= 5 rupees

20+10+5=35

Answer 2

Answer:

20 number of coins of each type are there in a bag.

Step-by-step explanation:

Given that a bag contains an equal number of one rupee coins, 50 paisa coins and 25 paisa coins respectively. If the total value is rs. 35/-

we have to find the number of coins of each type.

Let the number of coins of each type= x

Total Value = Rs. 35

Now,

$(1)x+x(50\thinspace paisa)+x(25\thinspace paisa)=35$

$x+\frac{x}{2}+\frac{x}{4}=35$

$\frac{4x+2x+x}{4}=35$

$\frac{7x}{4}=35$

$x=35\times \frac{4}{7}=20$

Therefore, 20 number of coins of each type are there in a bag.