Question

A bag contains cards bearing numbers
from 16 to 45. A card is taken out of the
bag at random. The probability of selected
card is a multiple of 5 is​

Answer 1

Answer:

total cards=30

favourable outcomes =6

p(e)= 6/30

=1/5

Answer 2

Answer:

The probability of selected card is a multiple of 5 = $\frac{1}{5}$

Step-by-step explanation:

Given,

A bag contains cards bearing numbers from 16 to 45 and a card is taken from the bag

To find,

The probability of the selected card is a multiple of 5

Recall the formula

Probability = $\frac{number \ of \ favorable \ outcomes}{Total \ number \ of \ outcomes}$

Solution:

Since the bag contains cards bearing numbers 16 to 45, total number of outcomes = Total numbers from 16 to 45 = (45-16)+1 = 30

Favorable outcomes = The multiple of 5 from 16 to 45

= {20,25,30,35,40,45}

The number of favorable outcomes = 6

Hence probability  = $\frac{number \ of \ favorable \ outcomes}{Total \ number \ of \ outcomes}$

= $\frac{6}{30}$

= $\frac{1}{5}$

∴ The probability of selected card is a multiple of 5 = $\frac{1}{5}$

#SPJ2