A bag contains cards numbered from 1 to 25. A card is drawn at random from the bag. The probability that the number on this card is divisible by both 2 and 3 is
(A) 1 5
(B) 3 25
(C) 4 25
(D) 2 25
Answers
Answered by
1
Here's You're Answer
Total number of possible outcomes = 25
Let E be the event that the number on the card drawn is divisible by both 2 and 3.
∴ E = {6, 12, 18, 24}
∴ Number of outcomes favourable to E = 4
P ( E ) = Number of favourable outcomesTotal number of outcomes = 4 25
Hence, the correct option is C.
Total number of possible outcomes = 25
Let E be the event that the number on the card drawn is divisible by both 2 and 3.
∴ E = {6, 12, 18, 24}
∴ Number of outcomes favourable to E = 4
P ( E ) = Number of favourable outcomesTotal number of outcomes = 4 25
Hence, the correct option is C.
Answered by
0
Hey mate here is ur answer,......
Total no of outcomes = 25
probablity of getting divisibilty by both 2 and 3 = ( 6, 12,18,24) = 4
So the answer is = C) 4 25
Hope it helps♥
Total no of outcomes = 25
probablity of getting divisibilty by both 2 and 3 = ( 6, 12,18,24) = 4
So the answer is = C) 4 25
Hope it helps♥
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