Question

A bag contains cards numbered from 1 to 25 . a card is drawn at random from the bag.find the probability that number is divisible by both 2 and 3

Answer 1

s = { 1 , 2 , 3 ... ,25 }

n ( s ) = 25

A is event that card drown is divisible by 2 and 3

A = { 6 , 12 , 18 , 24 }

n ( A ) = 4

p ( A ) = n(A )/n( S )

= 4/25

Answer 2

The given question is A bag contains cards numbered from 1 to 25 . a card is drawn at random from the bag. find the probability that the number is divisible by both 2 and 3

The given data is

There are 25 cards in the bag.

A card is drawn at random.

we have to find the probability that the card drawn at random is divisible by both 2 and 3.

The total sample space for the given question is

$n(s) = 25$

The number below 25 that are divisible by 2 are

2,4,6,8,10,12,14,16,18,20,22,24.

The numbers below 25 that are divisible by 3 are.

3,6,9,12,15,18,21,24.

The common number between the above series is

6,12,18,24

Therefore, the numbers that are divisible by both 2 and 3 are

6,12,18,24

The a be the event of getting a number that is divisible by both 2 and 3

$p(a) = \frac{n(a)}{n(s)}$

where n(a)= 4

let's substitute the value in the formula we get,

$\frac{4}{25}$

Therefore, the probability of the number that is divisible by both 2/ and 3 is 0.16

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