Question

A bag contains cards numbered from 2 to 25. A card is drawn at random from the bag. Find the probability that selected card bears a number which is mulitiple of 2 and 3

Answer 1

Total number of cards= 24

Number of cards that have multiple of both 2 and 3= 6,12,18,24 = 4

Probability= Favorable Outcomes/ Total number of Outcomes

P(getting a card with multiple of both 2 and 3)= 4/24 = 1/6 

Answer 2

total no of cards=24
no of cards that are multiples of 2 and 3 are 6,12,18,24
probability =no of favourable outcomes /total no of favourable outcomes
                =4/24
                =1/6