Question

A bag contains cards which are numbered from 2 to 90. A card is drawn at random from the bag. Find the probability that it bears a) a two-digit number, b) a number which is a perfect square

Answer 1

total no. of events =90-2+1=81

no. of fav. events =90-9=81

p(e)=81/89

so the probability that bears two digit no. is 81/89.

no. of fav. events = 4,9,16,25,36,49,64,81

p(e)=8/89

no. of probability which is perfect sq. is 8/89

Answer 2

Thank you for asking this question, here is your answer:

Total no. of possible outcomes = 89 {2, 3, 4, …., 90}

i) Let E be the event of getting a 2 digit no.

No of favorable outcomes = 81 {10, 11, 12, 13, ….., 80}

P(E) = (No.of favorable outcomes) will be divided by (Total no.of possible outcomes)

= 81/89

ii) Let E be the event of getting a no. which will be the perfect square

No. favourable outcomes = 8 {4, 9, 16, 25, 36, 49, 64, 81}

P(E) = 8/89

If there is any confusion please leave a comment below.