Math, asked by sandy9491, 1 year ago

A bag contains cards which are numbered from 2 to 90. A card is drawn at random from the bag. Find the probability that it bears a) a two-digit number, b) a number which is a perfect square

Answers

Answered by alirizvi8860292174
220

total no. of events =90-2+1=81

no. of fav. events =90-9=81

p(e)=81/89

so the probability that bears two digit no. is 81/89.

no. of fav. events = 4,9,16,25,36,49,64,81

p(e)=8/89

no. of probability which is perfect sq. is 8/89

Answered by Shaizakincsem
120

Thank you for asking this question, here is your answer:


Total no. of possible outcomes = 89 {2, 3, 4, …., 90}


i) Let E be the event of getting a 2 digit no.


No of favorable outcomes = 81 {10, 11, 12, 13, ….., 80}


P(E) = (No.of favorable outcomes) will be divided by (Total no.of possible outcomes)


= 81/89


ii) Let E be the event of getting a no. which will be the perfect square


No. favourable outcomes = 8 {4, 9, 16, 25, 36, 49, 64, 81}


P(E) = 8/89


If there is any confusion please leave a comment below.

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