A bag contains coins of 1 rupee 2 rupee and 5 rupee in tbr ratio 4:8:5.Thr total amount in bag is 90
Answers
Answered by
0
1 rupee= 4x
2 rupee=8x
5 rupee= 5x
Total rupee=90
4x+8x+5x=90
17x=90
x=90/17
x=5.3 approx
1 rupee= 4x=4×5.3=21.2
2 rupee= 8x=8×5.3=42.3
5 rupee= 5x=5x5.3=26.5
Total = 90
2 rupee=8x
5 rupee= 5x
Total rupee=90
4x+8x+5x=90
17x=90
x=90/17
x=5.3 approx
1 rupee= 4x=4×5.3=21.2
2 rupee= 8x=8×5.3=42.3
5 rupee= 5x=5x5.3=26.5
Total = 90
Similar questions