Question

a bag contains coins of denomination of 50 paise and five rupees the total value of these coins is Rs300 if the total number of coins in the bag is 150 find the number of coins of each type

Answer 1

let 50 paise coins be x
5 rupees coins will be (150-x) as there are q50 coins in the bag
50 paise = 100/50=1/2 rupees
1/2(x)+5(150-x)= 300 rupees
x/2+750-5x = 300 rs
-9x/2+750= 300
750-300 = 9x/2
450= 9x/2 => 9x = 900 => x=900/9 = 100 (50-paise coins )
5rupees coins => 150-x => 150-100=> 50 coins
hope this helps

Answer 2

If a bag contains a certain number of 50 paise and 5 rupees,then 50 paise in rupees = 0.5 rupees.
According to your question total number of coins = 150 which is equal to the sum of the number of denomination or coins of each type(let them be x and y) = x + y = 150 => x = 150 - y
The total value of these denominations = 300 then the coins with the denomination i.e. 0.5x + 5y = 300
=>0.5(150-y) + 5y = 300
=>75-0.5y + 5y = 300
=>4.5y = 225
=>y = 225 ÷ 4.5 = 50
So,
x + y = 150
=>x + 50 = 150
x = 100
Therefore,the number of 50 paise coin = 100 and the number of 5 rupees coin = 50.