A bag contains coins of denomination of Rs. 5&Rs.2.The total value of these coins is Rs. 1272.If the total no. of Rs. 2 coin is 15% of the 5 rupee coins, find the no. of coins of each denomination
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Let the no. of 5 rupees coin be x.
therefore the no. of 2 rupees coin = 15x/100 = 3x/20.
The value of 5 rupees coins = 5 * x = Rs. 5x.
The value of 2 rupees coins = 2 * 3x/20 = Rs 3x/10.
According to question
5x + 3x/10 = 1272.
50x + 3x =1272 * 10.
53x = 12720
x = 12720/53 = 240.
Thus,
the no. of 5 rupees coins = 240.
and the no. of 2 rupees coins = 240 * 3/20 = 36.
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Answer:
240
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