A bag contains coins of denomination of Rs. 5 and Rs. 2. The total value of these coins is Rs. 1272. If the number of two rupee coin is 15% of the five rupee coins, find the number of coins of each denomination
Answers
Answered by
15
Let the no. of 5 rupees coin be x.
therefore the no. of 2 rupees coin = 15x/100 = 3x/20.
The value of 5 rupees coins = 5 * x = Rs. 5x.
The value of 2 rupees coins = 2 * 3x/20 = Rs 3x/10.
According to question
5x + 3x/10 = 1272.
50x + 3x =1272 * 10.
53x = 12720
x = 12720/53 = 240.
Thus,
the no. of 5 rupees coins = 240.
and the no. of 2 rupees coins = 240 * 3/20 = 36.
Hope it helps bro
therefore the no. of 2 rupees coin = 15x/100 = 3x/20.
The value of 5 rupees coins = 5 * x = Rs. 5x.
The value of 2 rupees coins = 2 * 3x/20 = Rs 3x/10.
According to question
5x + 3x/10 = 1272.
50x + 3x =1272 * 10.
53x = 12720
x = 12720/53 = 240.
Thus,
the no. of 5 rupees coins = 240.
and the no. of 2 rupees coins = 240 * 3/20 = 36.
Hope it helps bro
Similar questions