Question

A bag contains five green marbles, three blue marbles, two red marbles, and two yellow marbles. One marble is drawn out randomly.
a) Are the four different colour outcomes equally likely? Explain.
b) Find the probability of drawing each colour marble i.e. , P(green), P(blue), P(red) and P(yellow)
c) Find the sum of their probabilities.​

Answer 1

Answer:

a) They are not equally likely because the number of marbles are different for each colour

b) P( green) = 5/ 12

   P( blue) = 3/ 12 = 1/4

   P( red) = 2/ 12 = 1/6

   P( yellow) = 2/ 12 = 1/6

c) sum of their probablities = 5/ 12 + 3/ 12 + 2/ 12 + 2/ 12 = 1

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Total number of marbles in the bag = 5 + 3 + 2 + 2 = 12.

(a)

No. Because, the bag contains all the different color marbles.

(b)

P(Green) = 5/12

P(Blue) = 3/12 = 1/4.

P(Red) = 2/12 = 1/6.

P(Yellow) = 2/12 = 1/6.

(c)

Sum of their probabilities = P(Green) + P(Blue) + P(Red) + P(Yellow)

                                          = (5/12) + (1/4) + (1/6) + (1/6)

                                          = (5/12) + (3/12) + (4/12)

                                          = 12/12

                                          = 1.

Hope it helps!