Question

a bag contains in all 50 balls some of them are white some are blue and some are red the number of white balls is 11 times the number of Blue Balls the number of red balls is less than the number of white balls also the number of red balls is more than the number of Blue Balls if one of the balls is selected at random from the bag what is the probability that is red

Answer 1

Solution:

Total number of Balls = (White +Red +Blue)=50

Also, Number of White Balls= 11 ×  Number of Blue Balls

→Let number of blue Balls = x

So, Number of white balls = 11 x

So, number of Red balls = 50 - (11 x +x)= 50 - 12 x

So, if one ball is selected at random , probability of getting red ball

  $=\frac{50-12 x}{50}=\frac{25-6x}{25}{\text{Probability of an event}}=\frac{\text{Total favorable Outcome}}{\text{Total Possible Outcome}}$

Total favorable Outcome= Selecting one red ball from (50-2 x) balls

$=_{1}^{50-2 x}\textrm{C}=\frac{(50-2x)!}{(49-2x)!\times 1!}= 50 - 2x$

Total Possible outcome $_{1}^{50}\textrm{C}=\frac{50!}{49!\times1!}=50$