a bag contains in all 50 balls. Some of them are white, some are blueand some are red. The no. of white balls is 11 times the no. of blue balls. The no. of red balls is less than the no. of white balls. Also thr no. of red balls is more than the no. of blue balls. If one of the balls is selected at random, what is the probability that it is red ?
Step by step explaination plzzzz.....
Std. X
Algebra
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Answer:
Probability of getting a red ball = 14/50 = 0.28
Step-by-step explanation:
W + B + R = 50
Let the number of blue balls be x.
Therefore, W = 11x, B = x and R = 50-12x
The no of red balls is less than no of white balls. Hence,
R < W
50-12x < 11x
50 < 23x
x > 50/23
x > 2.17 (First condition)
It is also given that the no of red balls is more than the no of blue balls. Hence,
R > B
50-12x > x
50 > 13x
x < 50/13
x < 3.84 (Second condition)
Putting the two conditions together:
2.17< x < 3.84
Since x has to be an integer, therefore, x = 3.
Therefore, number of blue balls is 3.
Number of red balls is 50-12(3) = 14.
Therefore, probability of getting a red ball = 14/50 = 0.28
manasi225:
Thanks
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