A bag contains INR.58,000 in the form of INR.10, INR.20 and INR. 100 notes in the ratio 2:3:5. The number of INR.20 notes in the bag is
Answers
Answer:
300
Step-by-step explanation: let INR 10 = 2x INR 20 = 3x INR 100 = 5x
10(2x)+20(3x)+100(5x)=58000
580x=58000
x=100
INR.20=3(100)=300
Answer:
The number of INR.20 notes in the bag is 300.
Step-by-step explanation:
Total money contains in bag = INR.58,000
According to the question,
Bag contains INR.10, INR.20 and INR.100 notes in the ratio 2:3:5.
Let the common ratio be x.
Then,
Number of INR.10 notes = 2x
Number of INR.20 notes = 3x
Number of INR.100 notes = 5x
Total amount of INR.10 notes = 10 × 2x
= INR. 20x
Total amount of INR.20 notes = 20 × 3x
= INR. 60x
Total amount of INR.100 notes = 100 × 5x
= INR. 500x
Now,
Total money = 20x + 60x + 500x
⇒ 58,000 = 20x + 60x + 500x
⇒ 58,000 = 580x
⇒ x = 100
Therefore, the number of INR.20 notes in the bag = 3 × 100
= 300 notes
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