Math, asked by traptigupta126, 10 months ago

A bag contains INR.58,000 in the form of INR.10, INR.20 and INR. 100 notes in the ratio 2:3:5. The number of INR.20 notes in the bag is

Answers

Answered by omgyyhg2003
1

Answer:

300

Step-by-step explanation: let INR 10 = 2x   INR 20 = 3x   INR 100 = 5x

10(2x)+20(3x)+100(5x)=58000

580x=58000

x=100

INR.20=3(100)=300

Answered by ushmagaur
0

Answer:

The number of INR.20 notes in the bag is 300.

Step-by-step explanation:

Total money contains in bag = INR.58,000

According to the question,

Bag contains INR.10, INR.20 and INR.100 notes in the ratio 2:3:5.

Let the common ratio be x.

Then,

Number of INR.10 notes = 2x

Number of INR.20 notes = 3x

Number of INR.100 notes = 5x

Total amount of INR.10 notes = 10 × 2x

                                                 = INR. 20x

Total amount of INR.20 notes = 20 × 3x

                                                 = INR. 60x

Total amount of INR.100 notes = 100 × 5x

                                                   = INR. 500x

Now,

Total money = 20x + 60x + 500x

⇒ 58,000 = 20x + 60x + 500x

⇒ 58,000 = 580x

⇒ x = 100

Therefore, the number of INR.20 notes in the bag = 3 × 100

                                                                                     = 300 notes

#SPJ2

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