Math, asked by bikashpalaka, 3 months ago

a bag contains lemon flavoured candies only. Malini takes out one candy without looking into bag. what is the probability that she takes out (i) on orange flavoured candy? (ii) a lemon flavoured candy? ​

Answers

Answered by somya2563
9

Step-by-step explanation:

Let E be the event of taking out a candy from bag.

Solution(i):

The bag contains only lemon flavored candies, and nothing else.

There are no orange flavored candies in the bag. Hence there is no possibility of taking out an orange candy.

➔ Therefore, the probability of taking out an orange flavored candy =0

Solution(ii):

The bag contains only lemon flavored candies, and nothing else.

Therefore (No.of favorable outcomes)=(Total no.of possible outcomes)

We know that, Probability of an event E, P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

P(E)=1

➔ Therefore, the probability of taking out a lemon flavored candy =1

Hope it helps...❤️✌️

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Answered by BeautifulWitch
1

Answer:

(i) Consider the event related to the experiment of taking out of an orange flavoured candy from a bag containing only lemon flavoured candies. Since no outcome gives an orange flavoured candy, therefore, it is an impossible event. So its probability is 0.

(ii) Consider the event of taking a lemon flavoured candy out of a bag containing only lemon flavoured candies. This event is a certain event. So its probability is 1.

Step-by-step explanation:

Hope this helps you ✌️

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