A bag contains n white and n black balls, all of equal size. Balls are drawn at random.
Find the probability that there are both white and black balls in the draw and that the
number of white balls is greater than those of black balls by one.
Answers
Answered by
0
Answer:
50%
Step-by-step explanation:
The number of balls is same
Probability (white) = n/2n = 1/2
Probability (Black)= n/2n = 1/2
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