a bag contains one ball known to be either black or white a black ball is put in bag is shaken and a ball is drawn out.what is the probability of the remaining ball being black,if the ball drawn is of the following types?i black ii white
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A bag contains one ball known to be either black or white a black ball is put in bag is shaken and a ball is drawn out.what is the probability of the remaining ball being black,if the ball drawn is of the following types?i black ii white
a bag contains one ball known to be either black or white
Case 1 : Bag Contains White Ball
Black Ball put Inside
Inside is White & Black
if Black is removed
Probability of remaning Black inside = 0
if White is Removed
Probability of renaming Black inside = 1
Case 2 : Bag Contains Black Ball
Black Ball put Inside
Inside is 2 Black
if Black is removed
Probability of remaining Black inside = 1
if White is Removed ( this case not possible)
Each assumed case has Equal Probability
the probability of the remaining ball being black,if the ball drawn is of Black
= (1/2) ( 0 + 1) = 1/2
the probability of the remaining ball being black,if the ball drawn is of White
= 1 ( as only one possible case)
Answer:
Step-by-step explanation: