Question

A bag contains one rupee, 50 paise and
25 paise coins in the ratio 5:6:8. If the
total amount is 420, then find the total
number of coins.​

Answer 1

Answer:

⇒ The ratio of Rs.1, 50 paise and 25 paise coins is 5:6:8

∴ Number of Rs.1 coins = 5x.

⇒ Number of 50paise coins = 6x

⇒ Number of 25paise coins = 8x.

∴ Value of 5x Rs.1 coins = Rs.1×5x=Rs.5x.

⇒ Value of 6x 50paise coins = 6x×50paise=Rs.

100

6x×50

=Rs.3x

⇒ Value of 8x 25paise coins = 8x×25paise=Rs.

100

8×25

=Rs.2x

⇒ Total amount = Rs.420

∴ 5x+3x+2x=420

∴ 10x=420

∴ x=

10

420

=42

∴ Number of Rs.1 coins = 5×42=210

∴ Number of 50paise coins = 6×42=252

∴ Number of 25paise coins = 8×42=336

⇒ Total number of coins = 210+252+336=798