Question

A bag contains one rupee 50 paise and 25 paise in the ratio of 5:6:8 amounting to 210

Answer 1

Answer:

105 Rs 1

126 50-paise

168 25-paise

Step-by-step explanation:

Rs 1 : Rs 0.50 : Rs 25 = 5 : 6 : 8

Define x:

Let x be the constant ratio:

Rs 1 : Rs 0.50 : Rs 0.25 = 5x : 6x : 8x

Solve x:

Total amount is Rs 210

5x(1) + 6x(0.5) + 8x(0.25) = 210

5x + 3x + 2x = 210

10x = 210

x = 21

Find the number of each denominations:

Rs 1 = 5x = 5(21) = 105

Rs 0.50 = 6x = 6(21) = 126

Rs 0.25 = 8x = 8(21) = 168

Answer: There are 105 Rs 1, 126 50-paise and 168 25-paise

Answer 2

Answer:

One rupee = 105

50 paise = 126

25paise = 168

Step-by-step explanation:

Given that : A bag contains 1 rupee , 50 paise and 25 paise in the ratio of 5:6:8 amounting 210

As we know that : 1 rupee = 100 paise

It means : 50 paise = 50/100 = 0.50 rupee

25 paise = 25/100 = 0.25 rupee

Let, 1 rupee = 5x

50 paise = 6x

And 25 paise = 8x in the bag

Now, according to the question :

(1×5x)+(0.50×6x)+(0.25×8) = 210

=> 5x+3x+2x = 210

=> 10x = 210

=> x = 21

Therefore : 1 rupee = 5×21 = 105

50 paise = 6×21 = 126

And 25 paise = 8×21 = 168

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