Question

A bag contains one rupee,50p,25p coins in ratio 5:6:8 amounting to ₹210. Find the number of coins of each type.

Answer 1

Answer:

1 RS = 105

50 paise = 126

25 paise = 168

Step-by-step explanation:

let the number of coins are = 5x ,6x and 8x

then we get

5x * 1 = 5x RS from 1 RS coin

6x * .5 = 3x RS from 50 paise coin

8x * .25 = 2x RS from 25 paise coin

so

5x + 3x + 2x = 210

10x = 210

X = 21

number of 1 RS coin = 5*21 = 105

number of 50 paise coin = 6*21 = 126

number of 25 paise coin = 8*21 = 168

Answer 2

Answer:

Given ratio of 1 rupee:50p:25p = 5:6:8

Let the number of ₹1=100p,50 p and 25p coins be 5x,6x,8x

Value of 100 p coin=(5x × 100/100)= 5x

Value of 50 p coin=(6x × 50/100)=3x

Value of 25 p coin=(8x × 25/100)=2x

A.T.Q

3x + 2x + 5x=210

10x=210

x=210/10

x=21

Therefore,

No.of 100p coins =21 × 5=105

No.of 50p coins=21 ×6=126

No. of 25p coins=21×8=168