Question

A bag contains one rupee,50paise and 25paise
coins in the ratio 5:6:8 amounting
to 210 rupees
Find the number of coins of
each type.​

Answer 1

Answer:

No.of one rupee coins = 5x = 105

No.of 50 paise coins = 6x = 126

No.of 25 paise coins = 8x = 168

Step-by-step explanation:

Given, A bag contains one rupee, 50paise and 25paise coins in the ratio 5:6:8

Let, No.of one rupee coins = 5x

No.of 50 paise coins = 6x

No.of 25 paise coins = 8x

Total amount = 210 rupees

210 = 5x(1) + 6x(0.50) + 8x(0.25)

210 = 5x + 3x + 2x

210 = 10x

x = 21

No.of one rupee coins = 5x = 105

No.of 50 paise coins = 6x = 126

No.of 25 paise coins = 8x = 168