A bag contains one rupee,50paise and 25paise
coins in the ratio 5:6:8 amounting
to 210 rupees
Find the number of coins of
each type.
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Answer:
No.of one rupee coins = 5x = 105
No.of 50 paise coins = 6x = 126
No.of 25 paise coins = 8x = 168
Step-by-step explanation:
Given, A bag contains one rupee, 50paise and 25paise coins in the ratio 5:6:8
Let, No.of one rupee coins = 5x
No.of 50 paise coins = 6x
No.of 25 paise coins = 8x
Total amount = 210 rupees
210 = 5x(1) + 6x(0.50) + 8x(0.25)
210 = 5x + 3x + 2x
210 = 10x
x = 21
No.of one rupee coins = 5x = 105
No.of 50 paise coins = 6x = 126
No.of 25 paise coins = 8x = 168
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