Question

A bag contains one rupee coins ,fifty paise coin and ten paise coins. The rupee coin and fifty paise coin are in the ratio 2:5 and fifty paise coins and ten paise coins in the ratio 4:9. If the total amount is 1575 then number of coins of ten paise exceeds the number of Rupee coin by:

Answer 1

Answer:

20

Step-by-step explanation:

Answer 2

The number of coins of ten paise exceeds the number of rupee coin by 2590.

Step-by-step explanation:

Since we have given that

Ratio of one rupee and fifty paise = 2 : 5

Ratio of fifty paise coins and ten paise coins = 4:9

Ratio of one rupee and fifty paise and ten paise would be

One rupee   :  Fifty paise   : Ten paise

  2                :           5              

                                4          :            9

------------------------------------------------------------

  8                 :         20         :         45

So, Amount earned from one rupee = 8x

Amount earned from fifty paise = $20x\times \dfrac{1}{2}=10x$

Amount earned from ten paise = $45x\times \dfrac{10}{100}=4.5x$

According to question, it becomes,

$8x+10x+4.5x=1575\\\\18x+4.5x=1575\\\\22.5x=1575\\\\x=\dfrac{1575}{22.5}\\\\x=70$

So, Number of ten paise would be $45\times 70=3150$

Number of one coin would be $8\times 70=560$

Difference between them is $3150-560=2590$

Hence, the number of coins of ten paise exceeds the number of rupee coin by 2590.

# learn more:

Which of the following money has the least value (a)ten twenty five paise coins and two five rupee coin(b)twenty fifty paise coins and five two rupee coin(c)fifty five paise coins and ten 50 paise coin(d)twenty twenty paise coins and ten two rupee coin

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