Question

A bag contains red counters and blue counters only Number of red counters:number of blue counters=3:4
Wride down the fraction of the counters which are red

Answer 1

Answer:

Hey!!

Answer is 3/7

Step-by-step explanation:

Total counters in a bag are= 3 +4

= 7

The fraction of the counters which are red are = Number of red counters

Total counters in bag

= 3

7

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Answer 2

Final Answer:

The fraction of the red counters in the bag containing the red counters and the blue counters in the ratio of 3:4 is $\frac{3}{7}$.

Given:

The bag contains the red counters and the blue counters only where the ratio of the number of red counters to the number of blue counters is 3:4.

To Find:

The fraction of the red counters in the bag containing the red counters and the blue counters in the ratio of 3:4 is to be calculated.

Explanation:

The essential concepts used in figuring out the solution to this problem are as follows.

• A fraction shows two parts, the numerator and the denominator.
• Here the numerator (x) of the fraction $\frac{x}{y}$ is used to indicate the upper part or portion of the fraction.
• Again, the denominator (y) of the fraction $\frac{x}{y}$ is used to indicate the lower part or portion of the fraction.

Step 1 of 2

Assume that the proportionality constant of the ratio 3:4 of the two types of counters is k.

So write the following parameters.

• The number of the red counters in the bag is $=3k$.
• The number of the blue counters in the bag is $=4k$
• The total number of both blue and red counters in the bag is

$=3k+4k\\=7k$

Step 2 of 2

Using the above information, it is clear that the part or fraction of the red counters in the bag is the number of the red counters in the bag divided by the total number of  counters in the bag.

In continuation with the above, the fraction of the red counters in the bag is

$\frac{3k}{7k}\\\\=\frac{3}{7}$

Therefore, the required correct answer is the fraction $\frac{3}{7}$ representing the counters which are red.

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