a bag contains rs 1 2 and 5 coins in the ratio of 5:9:4 amt to rs 129 find the no. of each type
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Answer:
bag contains 1 , 2 and 5 rupees coins
amount of 1 rs coin = 1×5x =5x
,, ,, 2 rs ,, =2×9x =18x
,, ,, 5 rs ,, = 5×4x=20x
5x+ 18x+ 20x = 129
43x = 129
× = 3
no of 1 rs coins = 15 (5×3)
2 rs coins = 27(9×3)
5 rs coins = 12(4×3)
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