A bag contains Rs 1, 50 paise and 25 paise coins in the ratio 5: 9: 25. If the total money in the bag is Rs 1008. If, the number of 50 paise coins is -
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We are given that A bag contains rupee, 50 paise and 25 paise coins in the ratio 5 : 7 : 9.
Let the ratio be x
So, No. of coins of Re.1 = 5x
Value of 5x coins of Re.1 = 5x
No. of coins of 50 paisa (Rs.0.5) = 7x
Value of 7x coins of 50 paisa = 7x(0.5)
No. of coins of 25 paisa ( Rs.0.25)=9x
Value of 9x coins of 25 paisa = 0.25(9x)
We are given that the total amount in the bag is rs. 430
So,
No. of coins of Re.1 = 4x= 4(40)=160
No. of coins of 50 paisa (Rs.0.5) = 7x =7(40)=280
No. of coins of 25 paisa ( Rs.0.25)=9x =9(40)=360
Hence there are 160 , 280 and 360 coins of re.1 , 50 paisa and 25 paisa respectively
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